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Tangent at a point P{other than (0, 0)} on the curve y = x3 meets the curve again at P2. The tangent at P2 meets the curve at P3, and so on. Show that the abscissa of P1, P2, P3,. ..., Pn, form a GP. Also find the ratio [area(Δ P1 P2 P3)]/[area(PPP4)]

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On putting the value of y in Eq. (i)

Therefore, x = -2h is the point P2,

Hence, the abscissa are h, -2h, 4h, -8h,... which form a GP.

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