Correct Answer - Option 3 : −1/3
\(\begin{array}{l}
\left| {9y - 6} \right| = 3\\
9y - 6 = \pm 3
\end{array}\)
Case 1:
\(9y - 6 = 3 \Rightarrow y - 1\)
Case 2:
\(9y - 6 = - 3 \Rightarrow y = \frac{1}{3}\)
Substitute \(y = 1\)
\({y^2} - \frac{{4y}}{3} = - \frac{1}{3}\)
Substitute \(y = \frac{1}{3}\)
\({y^2} - \frac{{4y}}{3} = - \frac{1}{3}\)
