Correct Answer - Option 3 : 41.66
Concept:
Median of a grouped data is given by:
\(Median = l + \frac{\frac{N}{2}-F}{f}\times h\) ----(1)
Where,
The class whose cumulative frequency is just greater than the value N/2 is called the median class.
Calculation:
Candidate Salary (in thousand) |
Number of Employees |
Cumulative frequency |
25-35 |
40 |
40 |
35-45 |
15 |
55 |
45-55 |
8 |
63 |
55-65 |
18 |
81 |
65-75 |
12 |
93 |
75-85 |
7 |
100 |
Here, N = 100
⇒ N/2 = 100/2 = 50
∴ The median class is 35-45
So, l = 35, f = 15, F = 40, N = 100, h = 10
\(⇒ Median = 35 + \frac{50-40}{15}\times 10\) [using(1)]
\(⇒ Median = 35 + \frac{10}{15}\times 10\)
⇒ Median = 35 + 6.66 = 41.66
Hence, median = 41.66