Question

An airplane accelerates down a runway at 3.20 m/s² for 32.8 s until it finally lifts off the ground. Determine the distance traveled before takeoff.
1. 1520 m
2. 1721 m
3. 1800 m
4. 1670 m

Answer 1

Correct Answer - Option 2 : 1721 m

The correct answer is 1721 m.

Explanation:

Given,

initial velocity (u) = 0

acceleration (a) = 3.20 m/s2

time (t) = 32.8 s

By using the formula \(s ={u}{ t}+ \dfrac {1}{2}at^2\)

⇒\(s =0+ \dfrac {1}{2} \times3.20 \times 32.8^2\)

⇒ \(s = 1721.344 \sim 1721 m.\)