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An airplane accelerates down a runway at 6 m/s2 for 40 s until it finally lifts off the ground. Determine the distance traveled before takeoff.
1. 4000 m
2. 4500 m
3. 4800 m
4. 5000 m

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Correct Answer - Option 3 : 4800 m

The correct answer is 4800 m.

Explanation:

Given,

initial velocity (u) = 0

acceleration (a) = 6 m/s2

time (t) = 40 s

By using the formula \(s ={u}{ t}+ \dfrac {1}{2}at^2\)

\(s =0+ \dfrac {1}{2} \times6 \times 40^2\)

⇒ \(s = 4800 m\) 

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