Question

A father is now two times as old as his son. Ten years back, he was three times as old as his son. The present age of the son (in years) is:
1. 15
2. 25
3. 20
4. 30

Answer 1

Correct Answer - Option 3 : 20

Let, age of Son = p

Age of Father = 2p

Ten years back:

Age of father = (2p - 10)

Age of son = (p - 10)

So;

Age of father = 3 × Age of son

(2p - 10) = 3 × (p - 10)

2p - 10 = 3p - 30

3p - 2p = 30 - 10

p = 20

So, age of son = 20 years.

Hence, "20" is the correct answer.