Given, Emf (E) = 12 V; r1 = 2Ω ; RA = 4Ω ; RB = 6Ω
1. The current in the circuit is
1 = E/Rtotal = E/R1 + RA + RB
I = 12/2 + 4 + 6 = IA
2. The terminal voltage of the cell is
Terminal Voltage = Emf- Ir,
Terminal Voltage= 12 – (1 × 2) = 12 – 2 = 10V
3. The potential difference across the 6Ω resistor is VB = IRB
∴ VB = 1 x 6 = 6V
4. The electrical energy spent per minute (= 60s) is
E = I2Rt
E = 12 × 4 × 60 = 240J