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The outermost shell configuration of an element is 4s24p3. The period to which the element belongs is
1. 5
2. 8
3. 3
4. 4

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Correct Answer - Option 4 : 4

The correct answer is 4.

 

  • According to the electronic configuration, the outermost shell tells us about the valence shell of the element.
  • So, the element has valency 4 and it belongs to the 4th Period of the Periodic table.
  • In 4s24p3, s and p are the subshells and 2 and 3 are the electrons in these subshells.

  • The electron configuration of an element describes how electrons are distributed in their atomic orbitals.
  • Electron configurations of atoms follow a standard notation in which all electron-containing atomic subshells (with the number of electrons they hold written in superscript) are placed in a sequence.
  • Shells:
    • The maximum number of electrons that can be accommodated in a shell is based on the principal quantum number (n).
    • It is represented by the formula 2n2, where ‘n’ is the shell number.
Shell and ‘n’ value Max. Electrons in the Electron Configuration
K shell, n=1 2*12 = 2
L shell, n=2 2*22 = 8
M shell, n=3 2*32 = 18
N shell, n=4 2*42 = 32
  • Subshells:
    • There are 4 subshells, s, p, d, and f.
    • Each subshell can hold a different number of electrons.
Subshell Electrons
s 2
p 6
d 10
f 14

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