Question

The mass of the belt per unit length in belt drive of pulleys is 10 kg/m. The maximum tension in a belt is 3000 N. The velocity of the belt for maximum power transmission:
1. 10 m/s
2. 5 m/s
3. 15 m/s
4. 20 m/s

Answer 1

Correct Answer - Option 1 : 10 m/s

Concept:

The velocity of the belt for maximum power:

\(v = \sqrt {\frac{T}{{3m}}} \)

where m = Mass of belt per unit length, T = Maximum tension in a belt.

Calculation:

Given:

T = 3000 N, m = 10 kg/m

\(v = \sqrt {\frac{T}{{3m}}} \) = \(\sqrt {\frac{3000}{{3\;\times\;10}}} \) = 10 m/s