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The velocity of a belt in belt drive mechanism is 5 m/s. The tension in tight side of belt is 2000 N while the tension in slack side of belt is 1000 N. The power transmitted in the belt drive is:
1. 5 kW
2. 1 kW
3. 2 kW
4. 1.5 kW

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Correct Answer - Option 1 : 5 kW


Power transmitted by a belt:

P = (Tt – Ts) × V

where Tt the tension on the tight side (N), Ts is the tension on the slack side (N), V is the velocity of the belt in m/s.



Tt = 2000 N, Ts = 1000 N, V = 5 m/s

P = (Tt – Ts) × V

P = (2000 - 1000) × 5 = 5000 Nm/s = 5 kW

∴ The power transmitted in the belt drive is 5 kW.

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