LIVE Course for free

Rated by 1 million+ students
Get app now
0 votes
22 views
in General by (54.3k points)
closed by
The velocity of a belt in belt drive mechanism is 5 m/s. The tension in tight side of belt is 2000 N while the tension in slack side of belt is 1000 N. The power transmitted in the belt drive is:
1. 5 kW
2. 1 kW
3. 2 kW
4. 1.5 kW

1 Answer

0 votes
by (30.0k points)
selected by
 
Best answer
Correct Answer - Option 1 : 5 kW

Concept:

Power transmitted by a belt:

P = (Tt – Ts) × V

where Tt the tension on the tight side (N), Ts is the tension on the slack side (N), V is the velocity of the belt in m/s.

Calculation:

Given:

Tt = 2000 N, Ts = 1000 N, V = 5 m/s

P = (Tt – Ts) × V

P = (2000 - 1000) × 5 = 5000 Nm/s = 5 kW

∴ The power transmitted in the belt drive is 5 kW.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...