Correct Answer  Option 4 : 125%
The correct answer is option 4) i.e. 125%
CONCEPT:

Kinetic energy is the energy possessed by a moving object. Kinetic energy (KE) is expressed as:
\(⇒ KE =\frac{1}{2} mv^2\)
Where m is the mass of the object and v is the velocity of the object.
 Momentum: Momentum is the impact due to a moving object of mass m and velocity v.
 The momentum (p) of an object is expressed as:
⇒ p = mv
EXPLANATION:
Let the initial and final linear momentum be p_{1} and p_{2}.
Let the initial and final kinetic energy be KE_{1} and KE_{2}.
We know, \(KE =\frac{1}{2} mv^2\)
Multiplying and dividing by m we get,
\(⇒ KE =\frac{1}{2} mv^2 \times \frac{m}{m} = \frac{p^2}{2m}\)
⇒ KE ∝ p^{2}
Let p_{1} = p
For 50% increase in linear momentum, p_{2} = 1.5 p_{1} = 1.5p
Then,
KE_{1} ∝ p^{2}
KE_{2} ∝ (1.5p)^{2}
Percentage change in kinetic energy \(= \frac{KE_2 KE_1}{KE_1} \times 100 \)
\(⇒ \frac{(1.5p)^2 p^2}{p^2} \times 100 \)
\(⇒ \frac{2.25  1}{1} \times 100 = 125\%\)
Thus, the change in kinetic energy is 125%.