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The kinetic energy possessed by two objects of mass 400 g and 200 g are in the ratio 1 : 2. Then the ratio of their linear momentum is
1. 1 : 1
2. 2 : 1
3. 1 : 2
4. 3 : 1

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Correct Answer - Option 1 : 1 : 1

The correct answer is option 1) i.e. 1 : 1

CONCEPT:

  • ​Kinetic energy is the energy possessed by a moving object. Kinetic energy (KE) is expressed as:

\(⇒ KE =\frac{1}{2} mv^2\)

Where m is the mass of the object and v is the velocity of the object.

  • Momentum: Momentum is the impact due to a moving object of mass m and velocity v.
  • The momentum (p) of an object is expressed as:

⇒ p = mv

CALCULATION:

Given that:

Mass of the two bodies:

m1 = 400 g = 0.4 kg

m2 = 200 g = 0.2 kg

The ratio of kinetic energy = \(\frac{KE_1}{KE_2} = \frac{1}{2}\)

We know,

\(⇒ KE =\frac{1}{2} mv^2\)

Multiplying and dividing by m we get,  

\(⇒ KE =\frac{1}{2} mv^2 \times \frac{m}{m} = \frac{p^2}{2m}\)

  • The relation between momentum and kinetic energy is given by

\(⇒ p =\sqrt{2mKE}\)

  • The ratio of linear momentum is given by

\(\Rightarrow \frac{p_1}{p_2} = \frac{\sqrt{2m_1KE_1}}{\sqrt{2m_2KE_2}} =\frac{\sqrt{m_1}}{\sqrt{m_2}} \times\frac{\sqrt{KE_1}}{\sqrt{KE_2}} = \sqrt{\frac{0.4}{0.2}} \times\sqrt{ \frac{1}{2}} = \frac{\sqrt{2}}{1} \times \frac{1}{\sqrt{2}} = \frac{1}{1}\)

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