Question

The average marks scored by a student in 6 exams is 96. His highest marks exceed his lowest marks by 12 marks. If these two exams were excluded, the average marks in the remaining exams is 94. The highest marks scored by the student is:
1. 108
2. 110
3. 105
4. 106

Answer 1

Correct Answer - Option 4 : 106

Given 

The average marks by a 6 student = 96 

Formula Used 

Average = Sum of observation/Number of observation

Calculations:

Average of 6 exams = 96.

Hence total marks of all the 6 exams = 6 × 96 = 576

Out of these 6, average of 4 exams = 94

Hence total marks of these 4 students = 4 × 94 = 376

So the total marks of the remaining 2 exams = 576 - 376 = 200

Highest marks = lowest + 12

Accordingly,

Heiighest + Lowest = 200

⇒ Lowest + lowesr + 12 = 200

⇒ 2 lowest = 188

⇒ Lowest = 188/2 = 94 marks 

Heighest marks = 94 + 12 = 106

∴ The required answer is 106 marks