Question

The income of A is 80% more than the income of B. If A's income is decreased by 20% and B's income is increased by 60%, then which of the following is true?

1. B's income is more than A's income by \(11\frac{1}{9}\)%
2. A's income is less than B's income by \(11\frac{1}{9}\)%
3. B's income is 16% more than A's income
4. A's income is equal to B's income

Answer 1

Correct Answer - Option 1 : B's income is more than A's income by \(11\frac{1}{9}\)%

Given:

A's income is 80% more than B's income

Calculation:

Let B's income be Rs. 100

A's income,

⇒ B's income + 80% of B's income

⇒ 100 + (80/100 × 100)

⇒ 180

Now A's income is decreased by 20%

⇒ 180 – (20/100) × 180

⇒ 180 – 36

A's new income is Rs. 144

Now B's income increased by 60%

⇒ 100 + (60/100) × 100

⇒ 100 + 60

B's new income is Rs. 160

B's income is more than A's income,

⇒ 160 – 144

⇒ 16

In percent,

⇒ 16/144 × 100

⇒ 1/9 × 100

⇒ \(11\frac{1}{9}\)%

∴ B's income is more than A's income by \(11\frac{1}{9}\)%