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A mixture of 80 liters of wine and water contains 60 percent wine. How much water must be added to make it 50 percent wine in the new mixture?
1. 18 liters
2. 12 liters
3. 20 liters
4. 16 liters

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Correct Answer - Option 4 : 16 liters

Given:

Mixture of wine and water = 80 liters

Initial winer concentration = 60%

Calculations:

Amount of wine in 80 litre of mixture = 60% of 80 = 48 litres

Amount of water in 80 litre of mixture =80 - 48 = 32  litres

Also, 50 percent wine in the new mixture means 50 percent water in the new mixture

Let x litres of water is added to the mixture

According to question,

⇒ 32 + x = 50/100 × (80 + x)

⇒ 2(32 + x) = (80 + x)

⇒ 64 + 2x = 80 + x

⇒ x = 16

∴ x = 16 litres

∴ 16 litres water must be added to make it 50 percent wine in the new mixture.

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