Correct Answer - Option 2 : 80
Given:
A person takes 40 minutes more than his usual time when he covers a distance of 20 km at 5 km/h. If he covers the same distance at 10 km/h, he takes x minutes less than the usual time.
Concept used:
Time and distance
Calculation:
Time = \(\frac{{{\rm{Distance}}}}{{{\rm{Speed}}}}\)
T1 = \(\frac{{20}}{5} = 4km/hr\)
T2 = \(\frac{{20}}{{10}} = 2km/hr\)
T1 : T2 = 2 : 1
Usual time = T1 and new time = T2
As per the question,
Difference of time = 40 unit
⇒ 2 unit - 1 unit = 40 unit
⇒ 1 unit = 40 unit
Usual time = 2 unit = 2 × 40
Usual time = 80