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The average score of a batsman in 62 innings is 42 runs. If his highest and lowest innings are removed then the average is decreased by 2. If the difference between the highest and lowest score is 196. Then find the higest score?
1. 200
2. 198
3. 202
4. 204

1 Answer

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Correct Answer - Option 1 : 200

Given:

Average of 62 innings is 42 runs.

Highest score – lowest score = 196

New average excluding highest and lowest innings = 40 runs

Formula used:

Average = Sum of observation/Total number of observation

Calculation:

Let the highest score be H and the lowest score be L.

Total run scored in 62 innings = 62 × 42 = 2604

Now, If his highest and lowest innings are removed then the average is decreased by 2

Total run excluding H and L = 60 × 40 = 2400

⇒ H + L = 2604 – 2400 = 204

⇒ H – L = 196

⇒ 2H = 400

⇒ H = 200

∴ The highest score scored by the batsman is 200 runs

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