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Find the total percentage of Magnesium in magnesium nitrate crystals, Mg(NO3)2 .6H2O/ [Mg = 24; N = 14; O = 16 and H = 1]

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Molar mass of Mg(NO3)2.6H2O

= 24 +(14 x 2) + (16 x 12) + (1 + 12) = 256 g

Mass percent of magnesium nitrate crystals

= 24/256 x 100

= 9.375%

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