
'.' For 123.5 g of Cu(II) carbonate 98 g of H2SO4 are required.
.'. 0.5 g of Cu(II) carbonate
= 98 x 0.5/123.5 g of H2SO4 are required.
Weight of required H2SO4 = 0.39676 g
Weight = mol.wt x molarity x volume in mL/1000
= 0.39676 = 98 x 0.5 x V/1000
Volume of H2SO4 solution = 8.097 mL