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How many millilitres of 0.5 M H2SO4 are needed to dissolve 0.5 g of copper(II) carbonate ?

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'.' For 123.5 g of Cu(II) carbonate 98 g of H2SO4 are required.

.'. 0.5 g of Cu(II) carbonate

= 98 x 0.5/123.5 g of H2SO4 are required.

Weight of required H2SO4 = 0.39676 g

Weight = mol.wt x molarity x volume in mL/1000

= 0.39676 = 98 x 0.5 x V/1000

Volume of H2SO4 solution = 8.097 mL

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