To form 5 dIgit numbers using all the digits 3. 8. 0. 7, 6.
0 should not be In the first place.
∴ From the remaIning 4 dIgits (3. 8. 7.6) one digit can be placed at the first placed In ways.
Now, remaining 4 digIts including O, can be arranged In remaIning 4 places in 4P4 ways.
Total permutations = 4P1 × 4P4
= 4 × 4!
= 4 × 24 = 96
