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यदि आव्यूह A = F(α) =  \(\begin{bmatrix}cosα &-sinα&0\\[0.3em]sinα&cosα&0\\[0.3em]0&0&1 \\[0.3em] \end{bmatrix}\)हो, तो A-1 ज्ञात कीजिए तथा सिद्ध कीजिए कि :

(i) A-1 A = I3

(ii) A-1 = F( – α)

(iii) A(adjA) = |A|I = (adjA).A

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दिया है आव्यूह

A = F(α) =  
\(\begin{bmatrix}cosα &-sinα&0\\[0.3em]sinα&cosα&0\\[0.3em]0&0&1 \\[0.3em] \end{bmatrix}\)

|A| = cos α (cos α – 0) + sin α (sin α – 0) + 0(0 – 0)

= cos2 α + sin2 α

| A | = 1 ≠ 0

अतः A-1 का अस्तित्व है।

आव्यूह A के सहखण्ड ज्ञात करने पर,

आव्यूह A के सहखण्डों से बना आव्यूह

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