Question

Mass in grams of copper deposited by passing 9.6487 A current through a voltmeter containing copper sulphate solution for 100 seconds is 

(Given : Molar mass of Cu : 63 g \(mol^{-1}\), 1 F = 96487 C) 

(1) 3.15 g 

(2) 0.315 g 

(3) 31.5 g 

(4) 0.0315 g

Answer 1

Correct option is (2) 0.315 g 

\(Cu^{2+} (aq) + 2e^- \rightarrow Cu(s)\)

Mass of Cu deposited (w) \(=\frac {M\times i \times t}{nF}\)

\(=\frac {63 \times 9.6487 \times 100}{2\times 96487}\)

= 0.315 g