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The temperature of 1 mole of an ideal monoatomic gas is increased by \(50^{\circ} \mathrm{C}\) at constant pressure. The total heat added and change in internal energy are \( E_{1} \ and\ E_{2}\), respectively. If \(\frac{E_{1}}{E_{2}}=\frac{x}{9}\) then the value of x is ____ .

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Answer is : 15

Given that process is isobaric \(\Delta \mathrm{T}=50^{\circ} \mathrm{C} \) 

Q in isobaric process \(=\mathrm{nC}_{\mathrm{p}} \Delta \mathrm{T}=\mathrm{E}_{1}\) 

\(\Delta \mathrm{U}\) in isobaric process \(=\mathrm{nC}_{\mathrm{v}} \Delta \mathrm{T}=\mathrm{E}_{2}\) 

\(\therefore \frac{E_{1}}{E_{2}}=\frac{C_{p}}{C_{v}}=\gamma\) 

Given, gas is monoatomic

\( \begin{aligned} \therefore \ \gamma & =1+\frac{2}{\mathrm{f}} \\ \end{aligned} \) 

\( = 1+\frac{2}{3}\) 

\( = \frac{5}{3}\)

Now, as per question.

\(\frac{5}{3} = \frac{x}{9}\)

\(x = 15\)

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