Question

In a simultaneous throw of pair of dice .find the probability of getting the total more than 7.

Answer 1

Here n(S)=(6*6)=36 

let E=event of getting a total more than 7 

={(2,6),(3,5),(3,6),(4,4),(4,5),(4,6),(5,3),(5,4),(5,5),(5,6),(6,2),(6,3),(6,4),(6,5 ),(6,6)} 

P(E)=n(E)/n(S)=15/36=5/12.