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If in a ∆ ABC, cosA/a = cosB/b = cosC/c then the triangle is (A) Right angled

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in Co-ordinate geometry by (63.6k points)

If in a ∆ ABC, cosA/a = cosB/b = cosC/c then the triangle is

(A) Right angled

(B) Isosceles

(C) Equilateral 

(D) Obtuse

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1 Answer

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Best answer

Correct option (C) Equilateral

Explanation:

From sine rule a/sinA = b/sinB = c/sinC = 2R

Given situation

a/cosA = b/cosB = c/cosB = k

2R sinA = k cosA 

tanA = tanB = tanC

Hence it is equilateral triangle.

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