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in Limit, continuity and differentiability by (41.5k points)

At which point the line x/a + y/b = 1,  touches the curve  y = be-x/a

(A) (0, 0) 

(B) (0, a) 

(C) (0, b) 

(D) (b, 0)

1 Answer

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Best answer

Answer is (C) (0, b)

Let the point be (x1, y1).

Therefore,

Now, the equation of tangent of given curve at point (x1, y2) is

Hence, the point is (0, b).

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