Question

Find the shortest distance between the lines L₁: (x – 2)/3 = (y – 3)/4 = (z – 4)/5 and L₂: (x – 2)/2 = (y + 1)/–1 = (z + 2)/3.

Answer 1

Here, r₁ = 2i + 3j + 4k

r₂ = 2i + j + 2k

and u = 3i + 4j + 5k

v = 2i – j + 3k

Now, (r₂ – r₁) = – 2j – 2k and