Question

Let L₁: (x – 1)/2 = (y – 2)/3 = (z – 3)/4 and L₂: (x – 2)/3 = (y – 4)/4 = (z – 5)/5 and A = (2, 3, 5). 

The shortest distance between the lines L₁ and L₂ is

Answer 1

Answer is (c) 1/√6

The shortest distance between two lines

= – i + 2j – k

and r₂ – r₁ = i + 2j + 2k

Hence, the shortest distance

Also, let A = (2, 3, 5)