Question

A dice is thrown once. The probability that the top face of dice contains a prime number is :

(A) \(\frac { 2 }{ 3 }\)

(B) \(\frac { 1 }{ 3 }\)

(C) \(\frac { 1 }{ 2 }\)

(D) \(\frac { 1 }{ 6 }\)

Answer 1

Answer is (C) \(\frac { 1 }{ 2 }\)

A dice is thrown once, the numbers that may be on the top face are 1, 2, 3, 4, 5, 6.

∴ The number of all possible out comes = 6

And the primes numbers are 2, 3 and 5.

∴ The number of favourable outcomes = 3.

∴ The required probability = \(\frac { 3 }{ 6 }\) = \(\frac { 1 }{ 2 }\)