Question

Consider the Plane \(\bar r\).(-6i -3j – 2k) + 1 = 0, find the direction cosines perpendicular to the Plane and perpendicular distance from the origin.

Answer 1

Convert the equation of the plane into normal form

Direction cosines perpendicular to the Plane is \(\frac{6}{7}, \frac{3}{7},\frac{2}{7}\)

Perpendicular distance from the origin is \(\frac{1}{7}\).