N2O5(g) → 2NO2(g) + 1/2 O2(g) In the above first order reaction the initial concentration of N2O5 is

Question

N₂O_5(g) →  2NO_2(g) + \(\frac{1}{2}\) O_2(g)

In the above first order reaction the initial concentration of N₂O₅ is 2.40 x 10^–2 mol L^–1 at 318 K. The concentration of N₂O₅ after 1 hour was 1.60 x 10^–2 mol^–1 . The rate constant of the reaction at 318 K is ..... x 10^-3min^-1 (Nearest integer) 

[Given : log₃ = 0.477, log 5 = 0.699]

Answer 1

Answer is (7)