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An aqueous solution of 2% non-volatile solute exerts a pressure of 1.004 bar at the normal boiling point of the solvent. What is the molar mass of the solute? 

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Vapour pressure of the solution at normal boiling point (p1) = 1.004 bar

 Vapour pressure of pure water at normal boiling point (po)=1.013 bar

Mass of solute, (w2) = 2 g

 Mass of solvent (water), (w1

= 98 g Molar mass of solvent (water), (M1)

 = 18 g mol−1 According to Raoult’s law, 

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