Correct Answer - Option 3 : 6.7 MHz
Concept:
In case of ripple or asynchronous counter total propagation delay Tpd = n tpd
Where n = no. of flip flops
tpd = propagation delay of each flip flop
If the strobe signal is given, the pulse width of the strobe is also added, i.e.
Tpd = n tpd + Ts
Calculation:
Given:
n = 4, tpd = 30 nsec, Ts = 30 nsec
Tpd = 4 × 30 + 30
Tpd = 120 + 30
Tpd = 150 ns
Maximum frequency at which counter operates will be:
\({f_{max}} = \frac{1}{{{T_{pd}}}}\)
Putting on the value, we get:
\(= \frac{1}{{180 \times {{10}^{ - 9}}}}\)
\(= \frac{{{{10}^3}}}{{180}}MHz = 6.67\;MHz.\)
≈ 6.7 MHz