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In a 4-stage ripple counter, the propagation delay of a flip-flop is 30 ns. If the pulse width of the strobe is 30 ns, the maximum frequency at which the counter operates reliably is nearly
1. 9.7 MHz
2. 8.4 MHz
3. 6.7 MHz
4. 4.4 MHz

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Correct Answer - Option 3 : 6.7 MHz

Concept:

In case of ripple or asynchronous counter total propagation delay Tpd = n tpd

Where n = no. of flip flops

tpd = propagation delay of each flip flop

If the strobe signal is given, the pulse width of the strobe is also added, i.e.

Tpd = n tpd + Ts

Calculation:

Given:

n = 4, tpd = 30 nsec, Ts = 30 nsec

Tpd = 4 × 30 + 30

Tpd = 120 + 30

Tpd = 150 ns

Maximum frequency at which counter operates will be:

\({f_{max}} = \frac{1}{{{T_{pd}}}}\) 

Putting on the value, we get:

\(= \frac{1}{{180 \times {{10}^{ - 9}}}}\) 

\(= \frac{{{{10}^3}}}{{180}}MHz = 6.67\;MHz.\) 

≈ 6.7 MHz

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