Correct Answer - Option 1 : 10 years
Given :
A is two years older than B
B is twice the age of C
Total of the ages of all three is 27 years
Calculation :
Let the age of A,B and C be 'x','y' and 'z' respectively, Then
⇒ x + y + z = 27 ------(1)
⇒ x = y + 2 ----- (2)
⇒ y = 2 × z
⇒ z = y/2 ----- (3)
From Eq (1), (2), and (3), we get
⇒ y + 2 + y + (y/2) = 27
⇒ 2.5 × y = 25
⇒ y = 10
∴ B is 10 years old