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In an exam, total marks gained by four students were 720.5. A got 10% less than B, B got 30% more than C and C got 25% less than D. If A got 175.5 marks, how much marks did D get in the examination?
1. 200
2. 150
3. 175
4. 250

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Correct Answer - Option 1 : 200

Given:

Total marks = 720.5

A got 10% less than B, B got 30% more than C and C got 25% less than D.

A got marks = 175.5

Calculation:

Marks obtained by given person in terms of another person = Marks obtained by another person +/- markspercentage by which another person obtains more/less marks than the given person

Calculation:

Let the marks obtained by D be x.

C got 25% less than D.

C = x – 25% of x

⇒ 75% of x = 0.75x

B got 30% more than C.

B = 0.75x + 30%of 0.75x

⇒ 0.75x + 0.225x

⇒ 0.975x

A got 10% less than B.

A = 0.975x – 10% of 0.975x

⇒ 0.975x – 0.10 × 0.975x

⇒ 0.8775x

A got marks = 175.5

⇒ 0.8775x = 175.5

⇒ x = 175.5/0.8775

⇒ x = 200 marks

∴ D obtained 200 marks. 

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