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in Three-dimensional geometry by (33.2k points)

Two lines L1: (x – x1)/a1 = (y – y1)/b1 = (z – z1)/c1

and L2: (x – x2)/a2 = (y – y2)/b2 = (z – z2)/c2 are coplanar if

|((x2 - x1,y2 - y1,z2 - z1),(a1,b1,c1),(a2,b2,c2))| = 0

If two lines (x – 1)/2 = (y – 2)/3 = (z – 3)/4 and (x – 4)/5 = (y – 1)/2 = z are coplanar, the point of intersection is

(a) (1, 1, 1)

(b) (1, –1, –1)

(c) (–1, –1, –1)

(d) (1, 1, –1)

1 Answer

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Best answer

Answer is (c) (–1, –1, –1)

Let

Hence, the point of intersection is (– 1, –1, –1).

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