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In a circle of diameter 40 cm, a chord is of length 20 cm. Find the length of the minor arc of the chord.

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O = centre of the circle 

PQ = diameter = 40 cm 

∴ OQ = 20 cm 

Radius = 20 cm 

⇒ OA = OB = 20 cm 

Chord AB = 20 cm 

OC ⊥ r AB 

∴ AC = CB = 10 cm 

Now from the right angled triangle OCB

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