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A shopkeeper sells two tables, each procured at cost price p, to Amal and Asim at a profit of 20% and at a loss of 20%, respectively. Amal sells his table to Bimal at a profit of 30%, while Asim sells his table to Barun at a loss of 30%. If the amounts paid by Bimal and Barun are x and y, respectively, then (x -y) / p equals
1. 0.7
2. 1
3. 0.50
4. 1.2

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Correct Answer - Option 2 : 1

Calculation:

Cost price of table for the shopkeeper = p

Cost price of table for Amal = (120/100) × p = 1.2p

Cost price of table for Asim = (80/100) × p = 0.8p

Cost price of table for Bimal = (130/100) × 1.2p = 1.56p

Cost price of table for Barun = (70/100) × 0.8p = 0.56p

⇒ x = 1.56p, y = 0.56p

⇒ (x – y)/p = (1.56 – 0.56)p/p = 1

∴ The value of (x – y)/p is 1.

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